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➜ Programming
➜ General
➜ Combining Variables
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| Posted by
| DB
(3 posts) Bio
|
| Date
| Tue 05 Mar 2019 02:18 AM (UTC) Amended on Tue 05 Mar 2019 02:48 AM (UTC) by DB
|
| Message
| Apologies in advance for the newbie question! Congrats on the Regexp library it is really useful!
My problem is if I match a message in quotes like ms.Match("63 100") my code works perfectly.
But I'd like to declare a variable in the beginning of the code so I don't need to change the values in the loop.
In the beginning of my code I'm declaring a variable like this:
char address = 63;
Then in the loop I want to match something like:
ms.Match (address, "100");
But as you know it does not work, I can't seem to find the right meta-character formatting to make it work.
Any suggestions please? | | Top |
|
| Posted by
| Nick Gammon
Australia (23,158 posts) Bio
Forum Administrator |
| Date
| Reply #1 on Tue 05 Mar 2019 04:46 AM (UTC) |
| Message
| Use sprintf to make the thing you want to match on, and then pass that string to ms.Match.
|
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| DB
(3 posts) Bio
|
| Date
| Reply #2 on Tue 05 Mar 2019 11:19 AM (UTC) Amended on Tue 05 Mar 2019 11:20 AM (UTC) by DB
|
| Message
| Thank you!
But then would I be creating a buffer with just two characters? Am I missing something? | | Top |
|
| Posted by
| Nick Gammon
Australia (23,158 posts) Bio
Forum Administrator |
| Date
| Reply #3 on Tue 05 Mar 2019 11:06 PM (UTC) |
| Message
| No, the buffer would have in it: 63 100
That’s what you want to match on isn’t it? In any case can’t use you strstr if you just want to find if one string is inside another?
|
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| DB
(3 posts) Bio
|
| Date
| Reply #4 on Wed 06 Mar 2019 11:39 AM (UTC) Amended on Wed 06 Mar 2019 11:40 AM (UTC) by DB
|
| Message
| Just because I didn’t know you could do that! Newbieism is a serious condition but I’m treating it! : )
Thanks Nick! | | Top |
|
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