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Subject:	table.remove stops for loop?
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Message:	[quote=Trevize] From what I've noticed it seems like when you use/call the routine (table.remove) in a table your looping it stops the loop?.. If thats the case it causes some problem for me. Here's a test I did: tableTest = { { name = "test1" }, { name = "test2" }, } function test() Note("tableTest1:") for k, v in tableTest do Note("k: " .. tostring(k) .. ". v.name: " .. tostring(v.name)) table.remove(tableTest, k) end Note("tableTest2:") for ke, ve in tableTest do Note("ke: " .. tostring(ke) .. ". ve.name: " .. tostring(ve.name)) end end Frist time I run function test. It shows: tableTest1: k: 1. v.name: test1 tableTest2: ke: 1. ve.name: test2 See, at tableTest1, it aborts the loop after the first table.remove. And then the second for loop, it shows that the table now only has the second value. The real function I actually noticed this in, is alot bigger. And it call's another function and from there I remove the value from a table that's looping in the first function, and I would like to be able to remove any amount from 0 to 1000 Is there anyway to bypass this or maybe make an alternative way of doing this? (and also, the reason I loop the table is becuase im checking it with another, so I "have" to loop the table.) [/quote] Message to be posted (in English, please).
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Posted by

Trevize (21 posts)

bio

Date

Sun 10 Jul 2005 11:02 PM (UTC) [ quote ]

Amended on Mon 11 Jul 2005 12:09 AM (UTC) by Trevize

Message

Ahh, thanks. Did't think about that, it makes sense..

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Posted by

David Haley USA (3,881 posts)

bio Moderator

Date

Sun 10 Jul 2005 10:37 PM (UTC) [ quote ]

Message

table.remove() shifts the array elements after the removed element down in the array. So if you remove element 1, element 2 becomes element 1. My hunch is that when you remove element 1, and then move to the next position, the iterator goes to position 2, which no longer exists in the array, and therefore stops as it detects end-of-array.

Chances are that if you were iterating over not an array but an associative table with named keys (as opposed to numbers), this would work.

In general - in most programming languages - it isn't necessarily safe to remove elements from a table as you iterate over it.

David Haley aka Ksilyan
Head Programmer,
Legends of the Darkstone

http://david.the-haleys.org

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Posted by

Trevize (21 posts)

bio

Date

Sun 10 Jul 2005 08:43 PM (UTC) [ quote ]

Message

From what I've noticed it seems like when you use/call the routine (table.remove) in a table your looping it stops the loop?.. If thats the case it causes some problem for me.

Here's a test I did:

tableTest = {
{ name = "test1" },
{ name = "test2" },
}

function test()

Note("tableTest1:")
for k, v in tableTest do
Note("k: " .. tostring(k) .. ". v.name: " .. tostring(v.name))
table.remove(tableTest, k)
end

Note("tableTest2:")
for ke, ve in tableTest do
Note("ke: " .. tostring(ke) .. ". ve.name: " .. tostring(ve.name))
end

end

Frist time I run function test.
It shows:
tableTest1:
k: 1. v.name: test1
tableTest2:
ke: 1. ve.name: test2

See, at tableTest1, it aborts the loop after the first table.remove. And then the second for loop, it shows that the table now only has the second value.

The real function I actually noticed this in, is alot bigger. And it call's another function and from there I remove the value from a table that's looping in the first function, and I would like to be able to remove any amount from 0 to 1000

Is there anyway to bypass this or maybe make an alternative way of doing this? (and also, the reason I loop the table is becuase im checking it with another, so I "have" to loop the table.)

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