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Subject review (reverse sequence)

Pages: 1 2  

Posted by Smokebomb   (6 posts)  [Biography] bio
Date Tue 03 Apr 2012 02:15 PM (UTC)  [ quote  ]
Message
ok so working backwards I realise I had made a couple of mistakes... this is now what my trigger looks like and is working just fine but I cant seem to be able to manipulate the key entry for 'area' (%3):


<triggers>
  <trigger
   enabled="y"
   match="You still have to kill * * (*)"
   send_to="12"
   sequence="100"
  >
  <send>campaign = {}
 -- create campaign table

campaign.mobs = {
 -- create sub table entries of campaign table

mob = "%2", area = "%3"
 -- gives the key 'mob' the value of the second wildcard and the key?! 'area' the value of the third wildcard

}
 -- close campaign table

print (campaign)
 -- prints campaign table

table.foreach (campaign.mobs, print)
 -- prints all the values of the subtables campaign.mobs


</send>
  </trigger>
</triggers>


which gives output that looks like this (for the last 4 mobs of the campaign):

table: 0x05dedd48
area The Blighted Tundra of Andarin
mob a pine tree
table: 0x05deb020
area The Labyrinth
mob a hippogriff
table: 0x05df3770
area The Wobbly Woes of Woobleville
mob An obnoxious goat

I want to be able to runto the area of the first key entry for 'area' and locate which room the mob is in by use of a trigger sending to script.


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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Tue 03 Apr 2012 02:08 AM (UTC)  [ quote  ]
Message
Why are you setting campaign to be an empty table?

Can you show some example output, describe what is actually happening, and what you expect to happen?
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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Posted by Smokebomb   (6 posts)  [Biography] bio
Date Mon 02 Apr 2012 11:57 PM (UTC)  [ quote  ]

Amended on Tue 03 Apr 2012 02:06 AM (UTC) by Nick Gammon

Message
err for some reason the above post copied 2 triggers at once... this is the one in question:


<triggers>
  <trigger
   enabled="y"
   match="Trigger: You still have to kill * * (*)"
   send_to="12"
   sequence="100"
  >
  <send>campaign = {}
mobs.mobname = {
mob = "%2", area = "%3"
}
print (campaign)

Send ("enter")
Send ("d")
Send ("runto %3")
Send ("where %2")
</send>
  </trigger>
</triggers>
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Posted by Smokebomb   (6 posts)  [Biography] bio
Date Mon 02 Apr 2012 11:55 PM (UTC)  [ quote  ]
Message
<triggers>
<trigger
enabled="y"
match="Finish * off!"
sequence="100"
sound="C:\Aardwolf\MUSHclient\sounds\Decapitation Head Blood-SoundBible.com-310864499.wav"
>
</trigger>
<trigger
enabled="y"
match="Trigger: You still have to kill * * (*)"
send_to="12"
sequence="100"
>
<send>campaign = {}
mobs.mobname = {
mob = "%2", area = "%3"
}
print (campaign)

Send ("enter")
Send ("d")
Send ("runto %3")
Send ("where %2")
</send>
</trigger>
</triggers>
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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Sat 31 Mar 2012 07:02 AM (UTC)  [ quote  ]
Message
Show the whole thing please:

Template:copying For advice on how to copy aliases, timers or triggers from within MUSHclient, and paste them into a forum message, please see Copying XML.
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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Posted by Smokebomb   (6 posts)  [Biography] bio
Date Fri 30 Mar 2012 09:54 PM (UTC)  [ quote  ]
Message
That's partly usefull because it does work however I need to be able to pull just the first set of %2 and %3 from the first table entry otherwise the script executes and it makes me run to every single area stored as the string for %3 for each entry (along with some additonal sends for 'hold portal' 'enter' 'down')

my trigger now looks like this :


Trigger: You still have to kill * * (*)

Send:
campaign = {}
mobs.mobname = {
mob = "%2", area = "%3"
}
print (campaign)
Send ("hold portal")
Send ("enter")
Send ("d")
Send ("hold candle")
Send ("runto %3")
Send ("where %2")

Send to: Script


So my question is - how do I pull/retrieve the first values and the first values ONLY for %2 and %3? - (because when the trigger executes next, the first entry of the table is the only one necessary for progressing, I believe the table is required to do this otherwise the script gets confused with all the different values of the wildcards.
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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Fri 30 Mar 2012 09:21 PM (UTC)  [ quote  ]
Message
To deal with the obvious problem:


runto "%3"
where "%2"


needs to be:


Send ("runto %3")
Send ("where %2")


This because, in a script, the Send function sends its arguments to the MUD.
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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Posted by Smokebomb   (6 posts)  [Biography] bio
Date Fri 30 Mar 2012 06:44 PM (UTC)  [ quote  ]
Message
ok so i took your advice nick and fiddled around with what i already knew, learnt a bit more in the process (after 2 days work(slow learner))

Trigger: You still have to kill * * (*)

Send:
campaign = {}
mobs.mobname = {
mob = "%2", area = "%3"
}
print (campaign)

Send to: script


This is all good and well in creating a table of campaign mobs in Aardwolf but I'm really struggling to find a way to manipulate the first 2 true wildcards (the 1st is recognised as an asterisk by the 1st wildcard).

Im pretty sure my main problem is that it's sending to script and not world so i can't put something like:

Send:
campaign = {}
mobs.mobname = {
mob = "%2", area = "%3"
}
print (campaign)
table.foreach (campaign, print)

runto "%3"
where "%2"

my second problem is i dont know how to differentiate/identify ((between)) different wildcard entries on different table entries

is there a special function or command that would make the ' runto "%3" ' and then the ' where "%2" ' - send to world within the script? Can I do it using another trigger or alias or have i got completely the wrong idea? My brain is telling me that i will need to identify which is the first table entry and the string values of %2 and %3 in that entry.

I'm quite lost here as you can tell.
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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Wed 29 Nov 2006 09:17 PM (UTC)  [ quote  ]

Amended on Wed 29 Nov 2006 09:21 PM (UTC) by Nick Gammon

Message
Quote:

return age.a < age.b


Semantically this is wrong anyway. This is comparing key "a" to key "b". That is, this is the same as:


return age ["a"] < age ["b"]


In other words, you are comparing the item "a" to the item "b", if they exist, which they don't in your case.

You really wanted:


return age [a] < age [b]


However my remarks about needing the numerically-indexed table still stand.
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Wed 29 Nov 2006 09:12 PM (UTC)  [ quote  ]

Amended on Wed 29 Nov 2006 09:14 PM (UTC) by Nick Gammon

Message
The sort function only works on numerically-indexed tables, whereas your tables has keys "peter", "paul" and "mary".

You can sort it, but you must first get a numerically-keyed table. This will do it:


age = {}
age.peter = 24
age.paul = 14
age.mary = 34


-- copy keys into numeric table
t = {}

for k in pairs (age) do
  table.insert (t, k)  -- remember key of each item
end -- for

-- show unsorted table
table.foreach (t, print)

-- sort it
table.sort (t, 
  function (a, b)
   return age [a] < age [b]
  end -- function
  )

-- show results

print "after sort..."

table.foreach (t, print)

Output

1 peter
2 mary
3 paul
after sort...
1 paul
2 peter
3 mary


What I have done here is first looped to copy the keys of your main table into a secondary (temporary) table t. You can see from the initial debugging display that they were added in the order peter, mary and paul (they are stored internally as a hash, so the order cannot really be predicted).

Now we sort the table t, using the keys to index into the age table to find which age is less than which other age.

Finally we can print the table t, which is now sorted into the correct order (paul, peter, mary).

This general technique can be used to sort anything into any sequence.
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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Posted by VincentVegas   (1 post)  [Biography] bio
Date Wed 29 Nov 2006 04:41 PM (UTC)  [ quote  ]
Message
Hello.

It might be that I am a bit dumb at the moment. :-)

I want to sort a table by its values, but that seems to be a real problem.

What I have is something like this:

age = {}
age.peter = 24
age.paul = 14
age.mary 34

I want to have this table sorted/printed according to their ages.

A table.sort(age) does nothing, nor does a table.sort(age,funcion (a,b) return age.a < age.b end)

What is the trick?

Regards
Thomas
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Posted by Siluri   (5 posts)  [Biography] bio
Date Mon 17 Apr 2006 02:33 PM (UTC)  [ quote  ]
Message
Perfect.

Thanks.
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Posted by David Haley   USA  (3,881 posts)  [Biography] bio   Moderator
Date Mon 17 Apr 2006 01:38 AM (UTC)  [ quote  ]
Message
How do you define stable/repeatable results? If you take a table with the same elements, the sort will always be the same, unless of course some elements are equal in which case their sort order is undefined.

To make things sort on multiple values, you could use something like this as your sort function:
function (a,b)
  if a.date < b.date
    return true -- primary sort
  elsif a.date == b.date
    return a.file < b.file -- secondary sort
  else
    return false -- a is >= b in this case (as far as the sort is concerned)
  end
end
David Haley aka Ksilyan
Head Programmer,
Legends of the Darkstone

http://david.the-haleys.org
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Posted by Siluri   (5 posts)  [Biography] bio
Date Mon 17 Apr 2006 01:11 AM (UTC)  [ quote  ]
Message
Hi Nick

Thanks for the advice so far.

I note that using table.sort doesn't produce stable/repeatable results.

Any advice on how to do this please?

Furthermore I'd like to be able to do sortation on two elements of a table (using above sample data, say primary sort on name, secondary sort on class). How would you do that using table.sort? (or would you put in full code for a sort into a function and do it that way?).

Thanks.
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Posted by Nick Gammon   Australia  (18,770 posts)  [Biography] bio   Forum Administrator
Date Tue 28 Mar 2006 10:38 PM (UTC)  [ quote  ]

Amended on Wed 29 Nov 2006 09:29 PM (UTC) by Nick Gammon

Message 

mastertable = nil


That will remove the reference to the table, and the garbage collector will collect it. Or, if you want to empty it, and keep it as a table:


mastertable = {}  -- make new, empty, table


If, for some reason, you need to keep the table the same (for example, you have references to it elsewhere), you can do this:


for k in pairs (mastertable) do
  mastertable [k] = nil
end -- for
- Nick Gammon

www.gammon.com.au, www.mushclient.com
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