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Message:	[quote=Nick Gammon] [quote=Paragate] If one has a string like this: s={"a","b","c","d-e"} Then string.find(s,"d-e") will return nil. [/quote] No, it doesn't. Test case: [code] s={"a","b","c","d-e"} a = string.find(s,"d-e") [/code] Results: [code]Run-time error World: Smaug Immediate execution \[string "Immediate"\]:3: bad argument #1 to 'find' (string expected, got table) stack traceback: \[C\]: in function 'find' \[string "Immediate"\]:3: in main chunk [/code] You can't pass a table to string.find. So, it's not a bug. [/quote] Message to be posted (in English, please).
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Posted by Paragate (5 posts) bio

Date Tue 08 Mar 2011 07:20 PM (UTC) [ quote ]

Message

Thank you very much for the reply.
The generic function solved my problem

I used:
local str=table.concat(s,",") first before I use
string.find(str,pat)

Thanks for the replay again.

Nick Gammon said:

Paragate said:

If one has a string like this:
s={"a","b","c","d-e"}

Then string.find(s,"d-e") will return nil.

No, it doesn't. Test case:


s={"a","b","c","d-e"}

a = string.find(s,"d-e")

Results:

Run-time error
World: Smaug
Immediate execution
[string "Immediate"]:3: bad argument #1 to 'find' (string expected, got table)
stack traceback:
        [C]: in function 'find'
        [string "Immediate"]:3: in main chunk

You can't pass a table to string.find. So, it's not a bug.

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Posted by Nick Gammon Australia (18,769 posts) bio Forum Administrator

Date Tue 08 Mar 2011 05:56 AM (UTC) [ quote ]

Message

Paragate said:

If one has a string like this:
s={"a","b","c","d-e"}

Then string.find(s,"d-e") will return nil.

No, it doesn't. Test case:


s={"a","b","c","d-e"}

a = string.find(s,"d-e")

Results:

Run-time error
World: Smaug
Immediate execution
[string "Immediate"]:3: bad argument #1 to 'find' (string expected, got table)
stack traceback:
        [C]: in function 'find'
        [string "Immediate"]:3: in main chunk

You can't pass a table to string.find. So, it's not a bug.

- Nick Gammon

www.gammon.com.au, www.mushclient.com

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Posted by Twisol USA (2,229 posts) bio

Date Tue 08 Mar 2011 (UTC) [ quote ]

Message

Paragate said:

If one has a string like this:
s={"a","b","c","d-e"}

This isn't a string, it's an array of strings. If you want to find a specific string within an array, you do:

local find_this = "d-e"

local idx = nil
for i,str in ipairs(s) do
  if str == find_this then
    idx = i
    break
  end
end

if idx then
  -- it was found
end

You can even wrap this up as a generic function:

table.find = function(t, match)
  for k, v in pairs(t) do
    if v == match then
      return k
    end
  end
  return nil
end


-- Usage:
local t = {"foo", "bar", "baz"}
local i = table.find(t, "bar")
Note(i) -- should be 2

'Soludra' on Achaea

Blog: http://jonathan.com/
GitHub: http://github.com/Twisol

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Posted by

Paragate (5 posts)

bio

Date

Mon 07 Mar 2011 11:31 PM (UTC) [ quote ]

Amended on Tue 08 Mar 2011 07:16 PM (UTC) by Paragate

Message

If one has a string like this:
s={"a","b","c","d-e"}

Then string.find(s,"d-e") will return nil.

The pattern I want to find is saved in a variable and it keeps changing, we don't know if the pattern to find has "-"
or not, so to add "%" is not a good option for me.

Anyway to solve this? thanks

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