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➜ SMAUG
➜ SMAUG coding
➜ const char *echo_strings[4]
|
const char *echo_strings[4]
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| Posted by
| Robert Powell
Australia (367 posts) Bio
|
| Date
| Mon 14 Jul 2014 09:25 AM (UTC) |
| Message
|
const char *echo_strings[4] = {
"The day has begun.\r\n",
"The day has begun.\r\n",
"The sky slowly begins to glow.\r\n",
"The sun slowly embarks upon a new day.\r\n"
};
Are the elements in this numbered 1-4 or 0-3 as I am making modifications to similar things and wish to use number_range rather than number_bits for selecting the random strings. |
Just a guy having a bit of fun. Nothing more, nothing less, I do not need I WIN to feel validated. | | Top |
|
| Posted by
| Nick Gammon
Australia (23,158 posts) Bio
Forum Administrator |
| Date
| Reply #1 on Mon 14 Jul 2014 10:04 PM (UTC) |
| Message
| | C arrays always start at zero. |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| Robert Powell
Australia (367 posts) Bio
|
| Date
| Reply #2 on Mon 14 Jul 2014 10:35 PM (UTC) Amended on Mon 14 Jul 2014 10:36 PM (UTC) by Robert Powell
|
| Message
|
Nick Gammon said:
C arrays always start at zero.
Why does the compiler complain if I change 4 to 3 then. 4 elements would be 0,1,2,3, but putting 3 instead of 4 gives error: too many initializers for ‘const char* [3]’
};
Kind of confused with what is happening, because i have some arrays that have 5 elements but with them, const char* [4] the compiler likes. |
Just a guy having a bit of fun. Nothing more, nothing less, I do not need I WIN to feel validated. | | Top |
|
| Posted by
| Nick Gammon
Australia (23,158 posts) Bio
Forum Administrator |
| Date
| Reply #3 on Tue 15 Jul 2014 (UTC) |
| Message
| You have 4 elements, I can see them.
As you say, they are 0, 1, 2, 3.
Total of 4, and thus you can have up to 4 initializers.
Quote:
Kind of confused with what is happening, because i have some arrays that have 5 elements but with them, const char* [4] the compiler likes.
Example code? |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
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