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question about capturing messages with regular expressions

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Posted by

Gunner Argentina (31 posts) Bio

Date

Thu 23 Jul 2020 12:38 AM (UTC)

Message

Hi.
I would like to know how to capture a message until the point in which there are multiple spaces in a row, and if after those spaces, there is more text, capture it in another wildcard.
Thanks

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Posted by Nick Gammon Australia (23,070 posts) Bio Forum Administrator

Date

Reply #1 on Thu 23 Jul 2020 03:26 AM (UTC)

Amended on Thu 23 Jul 2020 03:29 AM (UTC) by Nick Gammon

Message

This should do it:


^(.+) {2,}(.*)?$

To break that down:

^ --> Assert start of line
(.+) --> match anything, capture it
<space>{2,} --> match two or more spaces (note there is a space before the brace)
(.*)? --> match anything, capture it (optional)
$ --> Assert end of line

Example trigger:


<triggers>
  <trigger
   custom_colour="2"
   enabled="y"
   match="^(.+) {2,}(.*)?$"
   regexp="y"
   send_to="2"
   sequence="100"
  >
  <send>

wildcard 1 is: %1
wildcard 2 is: %2

</send>
  </trigger>
</triggers>

For advice on how to copy the above, and paste it into MUSHclient, please see Pasting XML.

- Nick Gammon

www.gammon.com.au, www.mushclient.com

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Posted by Gunner Argentina (31 posts) Bio

Date

Reply #2 on Thu 23 Jul 2020 12:32 PM (UTC)

Amended on Thu 23 Jul 2020 12:50 PM (UTC) by Fiendish

Message

OK, but don't work :)
My trigger is:
Match: ^\s*(\d+)\)\s\[(\d+)\]\s\w+\s+(.+) {2,}(.+) {2,}$

the message to capture is:


"6) [65] Consigue el Martillo del Alma                 Infierno                "

In the wildcard %3 the text is: "el martillo del alma infierno"
So I would like to capture "el martillo del alma" in the wildcard %3, and "infierno" in the wildcard %4

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Posted by Nick Gammon Australia (23,070 posts) Bio Forum Administrator

Date Reply #3 on Thu 23 Jul 2020 09:25 PM (UTC)

Message

It might have saved a day if you had mentioned your exact data in your first post.

Your problem here is that you have two places with multiple spaces, and the regexp isn't sure which one to stop at.

It might be easier to just capture the first part of the line (which is easy) and then use scripting to pull out up to the first lot of multiple spaces


<triggers>
  <trigger
   custom_colour="2"
   enabled="y"
   match="^\s*(\d+)\)\s\[(\d+)\]\s(.*)$"
   regexp="y"
   send_to="12"
   sequence="100"
  >
  <send>

print ("wildcard 1 is: %1")
print ("wildcard 2 is: %2")
print ("wildcard 3 is: %3")

first_part, second_part = string.match ("%3", "^(.-)%s%s+(.*)")

print ("first_part is", Trim (first_part))
print ("second_part is", Trim (second_part))

</send>
  </trigger>
</triggers>

The Lua pattern looks for anything (non-greedy) followed by two or more spaces, and then anything else.

- Nick Gammon

www.gammon.com.au, www.mushclient.com

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Posted by Fiendish USA (2,533 posts) Bio Global Moderator

Date

Reply #4 on Thu 23 Jul 2020 10:43 PM (UTC)

Amended on Thu 23 Jul 2020 10:46 PM (UTC) by Fiendish

Message

I don't think that's needed. Just make the ".+" nongreedy instead.

^\s*(\d+)\)\s\[(\d+)\]\s\w+\s+(.+?) {2,}(.+?) {2,}$

See https://regex101.com/r/f32tc7/1

https://github.com/fiendish/aardwolfclientpackage

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