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➜ MUSHclient
➜ Lua
➜ String problems
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| Posted by
| Gaem
(10 posts) Bio
|
| Date
| Thu 07 Dec 2006 10:36 PM (UTC) |
| Message
| I'm sure this question has probably been asked before, but I can't seem to find an answer in the usual documentation places.
I've run into a problem where I'm trying to compare two strings (from variables in MUSH), but modifying one with arithmetic.
eg.
function f1 (name, line, wildcards)
local variable1 = GetVariable("variable1")
local variable2 = GetVariable("variable2")
local variable3 = GetVariable("variable3")
if variable1 < 0.85 * variable2 then (here I have a problem, since it says I can't do arithmetic on a string)
Note ("yay!")
end
end -- function
Also, what is the syntax in lua for conditioning on 2 variables? So, as above, but requiring variable3 = 1 as well as variable1 < 0.85 * variable2.
Thanks | | Top |
|
| Posted by
| Nick Gammon
Australia (23,133 posts) Bio
Forum Administrator |
| Date
| Reply #1 on Thu 07 Dec 2006 10:44 PM (UTC) |
| Message
| |
| Posted by
| Gaem
(10 posts) Bio
|
| Date
| Reply #2 on Fri 08 Dec 2006 12:16 AM (UTC) |
| Message
| Thanks!
The first part works fine, but I get this error whenever I try to do if statements with 2 parts;
compile error
[string "Script file"]:63: 'then' expected near '='
I was using
if tonumber(var1) < 0.85 * tonumber(var2) and var3 = 1 then
as the line.
Any ideas as to what I'm doing wrong? | | Top |
|
| Posted by
| Nick Gammon
Australia (23,133 posts) Bio
Forum Administrator |
| Date
| Reply #3 on Fri 08 Dec 2006 12:31 AM (UTC) |
| Message
| Equality test is == not =.
Inequality is ~= (in Lua).
So yours should read:
if tonumber(var1) < 0.85 * tonumber(var2) and var3 == 1 then
The "=" operator is assignment. Thus you can write this:
This makes a true if b is equal to 2, false otherwise. |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| Gaem
(10 posts) Bio
|
| Date
| Reply #4 on Fri 08 Dec 2006 08:45 AM (UTC) |
| Message
| Thanks again!
That all works fine now.
| | Top |
|
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